Thursday, January 27, 2011

Output..?


#include<stdio.h>  
#include<conio.h>
void main()
{
enum c{c·34, d-12, a, b};
clrscr():
if(a== (1==2))
printf("%d", a);
else
printf("%d" , b) ;
}
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7 comments:

  1. KhushbooFebruary 2, 2011 at 7:27 AM

    khabar nai...confused!!!!

    ReplyDelete
  2. nishaFebruary 2, 2011 at 7:36 AM

    yeh enum main aise values daal sakte hain??

    ReplyDelete
  3. PrashantRajFebruary 2, 2011 at 10:16 AM

    Hey are you sure there is no typing mistake in it???

    ReplyDelete
  4. JayminFebruary 3, 2011 at 5:04 AM

    #include
    #include
    void main()
    {
    enum c{c=34, d=12, a, b};
    clrscr():
    if(a== (1==2))
    printf("%d", a);
    else
    printf("%d" , b) ;
    }

    ReplyDelete
  5. nishaFebruary 3, 2011 at 12:25 PM

    han now its a bit clear....

    ReplyDelete
  6. UnknownFebruary 4, 2011 at 3:08 AM

    in the statement 'if(a== (1==2))'
    as far as i know (1==2) will result in to 'false'.
    and it'll check if(a==false)
    but 'a' is not of boolean data type.
    so how this is going to be interpreted??

    ReplyDelete
  7. JayminFebruary 6, 2011 at 7:15 AM

    Output 14
    Explanation: Here tagname (c) and constant name (c) is same
    but still no errors. The values for constant names,
    c=34
    d=12
    a=13
    b=14
    if(a==(1==2)) this is FALSE because,
    if (a==(0)) —> (because 1==2 is not TRUE)
    if (13==0) —> FALSE Hence b's value is printed

    ReplyDelete

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